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  • ID: 5564639
  • Uploader: redtails »
  • Date: 2023-01-08 01:34
  • Update: 2026-08-04 00:49
  • Size: 900.7 KB .jpg (1191x1684) »
  • Top tagger: redtails (54)
  • Source: exhentai.org more
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This post belongs to a parent (learn more) « hide
Media asset #1
limit for h approaching 0 of 2 * cos( x + h/2 ) * sin( h/2 ) / h
for h approaching 0 on sin(h)~= h we divide both denominator and numerator by 2 to match the contents as we can see it will be 1 ence sin(h/2)/(h/2) ~= (h/2)/(h/2) -> 1 when h approaching 0 remains cos(x+h/2) that for h = 0 is cos(x)
Danbooru
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    limit for h approaching 0 of 2 * cos( x + h/2 ) * sin( h/2 ) / h
    for h approaching 0 on sin(h)~= h we divide both denominator and numerator by 2 to match the contents as we can see it will be 1 ence sin(h/2)/(h/2) ~= (h/2)/(h/2) -> 1 when h approaching 0 remains cos(x+h/2) that for h = 0 is cos(x)

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